time and distance Model Questions & Answers, Practice Test for ssc chsl tier 1 2024

Answer: (a)

Difference of distance covered by Police and thief is 100 m

Speed of Police = 10 km/h Speed of theif = 8 km/hr

let time be t

10 × $5/{18} t - 8 5/{18}t$ = 100 [∵ D = 8T]

${5t}/9$ = 100

t = 180 S

Theif ran = 8 × $5/{18}$ × 180 = 400 m

Answer: (c)

Time = ${\text"Distance"}/{\text"Speed"}$

Let distance travel from A to B be x km.

According to question

∴ 7 = $x/4 + x/3 = {x(3 + 4)}/{12} ={7x}/{12}$⇒x = 12 km

Answer: (b)

$t_2 – t_1 = 2h⇒ x/{10} - x/{15} = 2$

⇒${3x - 2x}/{30}$ = 2 Relative speed

x = 60 km.

= 15 – 10 = 5km 1h.

speed = ${distance}/{\text"relative speed"} = {60}/5$ = 12 km/h.

Answer: (d)

Time taken to travel 96 miles

= $96/11$ hrs. = 8 hrs and 43 minutes

During the journey of 96 miles, he has to stop for 13 times to change the horse.

∴ Total stoppage time

= 13 × 5 = 65 mins. = 1 hr and 5 mins.

Hence the total time

= 8 hrs and 43 mins + 1 hr and 5 mins.

= 9 hrs and 48 mins.

Answer: (d)

Ratio of speed = 2 : 3 : 4

Ratio of time = $1/2 : 1/3 : 1/4 = {12}/2 : {12}/3 : {12}/4$ = 6 : 4 : 3

So, option (d) is correct.